ANSWER
B = 0.18T
EXPLANATION
Given:
• The length of the wire, L = 12.4m
,• The current flowing through the wire, I = 9.4A
,• The force experimented by the wire, F = 21N
Unknown:
• The strength of the magnetic field, B
The equation for the force on a wire of length L in a perpendicular magnetic field of strength B while a current I is flowing through it is,
[tex]F=B\cdot I\cdot L[/tex]Solving for B,
[tex]B=\frac{F}{I\cdot L}=\frac{21N}{9.4A\cdot12.4m}\approx0.18T[/tex]Hence, the strength of the magnetic field is 0.18 Tesla.
