There are three boxes, each of which contains balls with numbers from 0 to 9. One ball is taken out of each box. What is the probability thata) three units are drawn;b) three equal numbers are drawn?

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SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the formula for probability

[tex]probability=\frac{number\text{ of required outcomes}}{number\text{ of total possible outcomes}}[/tex]

STEP 2: Write the number of outcomes

There are 0-9 numbers which are 0,1,2,3,4,5,6,7,8,9 which makes it 10 total possible outcomes.

STEP 3: Find the probability that three units are drawn

[tex]Pr(3\text{ units\rparen}=Pr(1\text{ unit\rparen}\times Pr(2nd\text{ unit\rparen}\times Pr(3rd\text{ unit\rparen}[/tex]

Find the probability that a unit is drawn:

[tex]Pr(1\text{ unit\rparen}=\frac{1}{10}[/tex]

The probability that three units are drawn will be:

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