[tex]\begin{gathered} \text{Given} \\ d=250\text{ ft} \\ s=\sqrt[]{24d} \end{gathered}[/tex][tex]\begin{gathered} \text{Substitute the given distance, to the given formula} \\ \\ s=\sqrt[]{24d},\text{ IF }d=250,\text{ THEN} \\ \\ s=\sqrt[]{24\cdot(250)} \\ s=\sqrt[]{6000} \\ s=77.4596669 \end{gathered}[/tex]
Rounding the answer to the nearest tenth, the speed of the vehicle before the brakes were applied is 77.5 mi/hr.
