Given equation:
[tex]2(3x+6)-96=6(2x-4)-56[/tex]Solve the equation to find the value of x,
[tex]\begin{gathered} 2(3x+6)-96=6(2x-4)-56 \\ 2(3x)+2(6)-96=6(2x)-6(4)-56 \\ 6x+12-96=12x-24-56 \\ 6x-84=12x-80 \\ -84+80=12x-6x \\ -4=6x \\ x=\frac{-4}{6} \\ x=-\frac{2}{3} \end{gathered}[/tex]Hence, x=-2/3
Answer: option B) is correct