Solution
For this case we can use the following formula:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]And for this case
n= 4 compounded quarterly
t= 10 years
A= 200000
P=?
r=0.06
And we can solve for P and we got:
[tex]P=\frac{200000}{(1+\frac{0.06}{4})^{4\cdot10}}=110252.5[/tex]So then the final answer would be:
110252.5