Answer
Explanation
Given:
2Al + 3Cl₂ 2AlCl₃
Molar mass of AlCl3 => 133 g/mol
Moles of Cl₂ = 25.0 mol
What to find:
The grams of aluminum chloride that can be produced.
Step-by-step solution:
Step 1: Determine the mole of AlCl₃ produced.
From the given chemical equation for the reaction,
3 mol Cl₂ produce 2 mol AlCl₃
So 25.0 mol Cl₂ will produce
[tex]\frac{25.0mol\text{ }Cl_2\times2mol\text{ }AlCl₃}{3mol\text{ }Cl_2}=16.67mol\text{ }AlCl₃[/tex]16.67 moles of AlCl₃ produced.
Step 2: Calculated the grams of AlCl₃ produced.
Using the mole formula
[tex]undefined[/tex]