Note that the data is in ascendinhg order.
We shall find the position of the pth percentile as follows;
[tex]\begin{gathered} i=\frac{p}{100}\times n \\ \text{Where } \\ p=70,n=50\text{ (number of data)} \end{gathered}[/tex]
We now have;
[tex]\begin{gathered} i=\frac{70}{100}\times50 \\ i=35 \end{gathered}[/tex]
In the 34th and 35th position we have;
[tex]\begin{gathered} \text{The 35th percentile is;} \\ (\frac{5.4+5.7}{2}) \\ =(\frac{11.1}{2}) \\ =5.55 \end{gathered}[/tex]
ANSWER:
[tex]P_{70}=5.55\text{Mbps}[/tex]
