We are given the following equation:
[tex]\frac{6}{19}=\frac{x-12}{2x-2}[/tex]To solve for "x" we will first multiply both sides by 19
[tex]6=\frac{19(x-12)}{2x-2}[/tex]Now we multiply both sides by "2x - 2":
[tex]6(2x-2)=19(x-12)[/tex]Now we solve the operations in the parenthesis using the distributive property:
[tex]12x-12=19x-228[/tex]Now we add 19x on both sides.
[tex]12x-19x-12=-228[/tex]Solving the operations:
[tex]-7x-12=-228[/tex]Adding 12 on both sides:
[tex]-7x-12+12=-228+12[/tex]Solving the operations:
[tex]-7x=-216[/tex]Dividing both sides by -7
[tex]x=-\frac{216}{-7}[/tex]Solving the operation:
[tex]x=\frac{216}{7}[/tex]Therefore the value of "x" is 216/7
