PLEASE PLEASE HELP ASAPIn parallelogram ABCD, AD=19, EC=15, mABC=66°, mDAC=78° and mBDC=19°.Find mABD.

we can see that
We know that, in a parallelogram the opposite angles are equal to each other, this means that
[tex]66=19+ADB[/tex]hence, we have that
[tex]\begin{gathered} \text{ADB}=66-19 \\ \text{ADB}=47 \end{gathered}[/tex]Now, from the figure, we can see that, in the triangle ADB, we know angle ADB=47 and angle DAB=78.
Since all interior angles of a triangle add up 180, we have
[tex]47+78+\text{ABD}=180[/tex]and from this equality, we can find angle ABD. It yields
[tex]\begin{gathered} 125+\text{ABD}=180 \\ \text{ABD}=180-125 \\ \text{ABD}=55 \end{gathered}[/tex]hence, the answer is ABD=55 degrees