The change in kinetic energy of the car can be given as,
[tex]\Delta K=\frac{1}{2}m(v^2-u^2)[/tex]After running to tree the car will stop therefore, the final speed of car is 0 m/s.
Substitute the knwon values,
[tex]\begin{gathered} \Delta K=\frac{1}{2}(1180kg)((0m/s)^2-(18.2m/s)^2) \\ =(590\text{ kg)(-}331.24m^2s^{-2})(\frac{1\text{ J}}{1kgm^2s^{-2}}) \\ =-195431.6\text{ J} \\ \approx-195000\text{ J} \end{gathered}[/tex]Thus, the magnitude of change in the kinetic energy of car is 195000 J.
