we have
[tex]\sqrt[4]{1,296}[/tex]Remember that
1,296=(36)^2
and 36=6^2
so
1,296=(6^2)^2=6^4
substitute
[tex]\sqrt[4]{1,296}=\sqrt[4]{6^4}=6[/tex]Part 2
we have
[tex]\sqrt[3]{0.125b^3}[/tex]we have that
0.125=125/1,000=(5/10)^3
substitute
[tex]\sqrt[3]{0.125b^3}=\sqrt[3]{(\frac{5}{10})^3b^3}=\frac{5b}{10}=0.5b[/tex]