Respuesta :
We will investigate the how to construct an algebraic equation and solve for a variable considering the word problem.
We will denote the cost of the cell phone at Store A as a variable:
[tex]\text{Cost of Cell phone ( A ) = x}[/tex]Similarly, the cost of cell phone at store B is given as follows:
[tex]\text{Cost of Cell phone ( B ) = \$44.99}[/tex]We will deconstruct the rest of the problem statement and translate into an algebraic equation that would relate the cost of cell phones at each store.
We are given that:
[tex]\text{Cost of cell phone at store A is \$10 less than twice the cost of cell phone at store B.}[/tex]So if we translate the above statement in terms of ( x ) and the cost of cell phone at store B we have:
[tex]\text{Cost of Cellphone ( A ) = 2 }\cdot\text{ ( 44.99 ) - 10}[/tex]Therefore,
[tex]x\text{ = 2}\cdot44.99\text{ - 10}[/tex]We will use the above equation and solve for the variable ( x ) by evaluating the right hand side of the " = " sign as follows:
[tex]\begin{gathered} x\text{ = 89.98 - 10} \\ x\text{ = \$79.98} \end{gathered}[/tex]Therefore, the cost of the cell phone at Store A is:
[tex]\text{Cost of cell phone at Store A = \$79.98}[/tex]