We want to solve the following equation:
[tex]2(6d+3)=18-3(16-3d)[/tex]
First, let's expand the parenthesis by using the distributive property.
[tex]\begin{gathered} 2(6d+3)=18-3(16-3d) \\ 12d+6=18-48+9d \\ 12d+6=-30+9d \end{gathered}[/tex]
Now, let's subtract 6 from both sides of the equation.
[tex]\begin{gathered} 12d+6-6=-30+9d-6 \\ 12d=-36+9d \end{gathered}[/tex]
Now, let's subtract 9d from both sides.
[tex]\begin{gathered} 12d-9d=-36+9d-9d \\ 3d=-36 \end{gathered}[/tex]
And finally. let's divide both sides by 3.
[tex]\begin{gathered} \frac{3d}{3}=-\frac{36}{3} \\ d=-12 \end{gathered}[/tex]
d = -12.
