The system of equations is
[tex]\begin{cases}3x+y=9 \\ 2x+2y=10\end{cases}[/tex]To solve that system let's subtract the equation, but first, one of the variables must have the same coefficient, to do that, let's divide the second equation by 2
[tex]\begin{cases}3x+y=9 \\ 2x+2y=10\text{ (}\div\text{2)}\end{cases}\Rightarrow\begin{cases}3x+y=9 \\ x+y=5\end{cases}[/tex]Now we have
[tex]\begin{cases}3x+y=9 \\ x+y=5\end{cases}[/tex]If we subtract the equations
[tex]\begin{gathered} (3x+y)-(x+y)=9-5 \\ \\ 2x=4 \\ \\ x=2 \end{gathered}[/tex]Then x = 2, it means that the point value of computation problems missed is equal to 2. Now we have the value of x we can use any equation to solve it for y.
[tex]\begin{gathered} x+y=5 \\ \\ 2+y=5 \\ \\ y=3 \end{gathered}[/tex]Therefore y = 3, the point value for each word problem is 3 points
