Given:
[tex]2m^3-14^{m2}+20m=0[/tex]
Aim:
We need to find the values of m.
Explanation:
Take out the common term 2m from the equation.
[tex]2m(m^2-7m+10)=0[/tex]
Divide both sides by 2.
[tex]\frac{2m}{2}(m^2-7m+10)=\frac{0}{2}[/tex]
[tex]m(m^{2-}7m+10)=0.[/tex][tex]Use\text{ -7m=-5m-2m.}[/tex]
[tex]m(m^2-5m-2m+10)=0.[/tex]
[tex]m(m(m-5)-2(m-5))=0.[/tex]
[tex]m(m-5)(m-2)=0.[/tex]
[tex]m=0,(m-5)=0,(m-2)=0.[/tex]
[tex]m=0,m=5,m=2.[/tex][tex]m=0,2,5.[/tex]
Final answer:
[tex]0,2,5.[/tex]
