What is the probability that he chooses a Q from the left box and an F from the right?(Answer in fraction form.)

The left box has 9 letters, 1 being Q
The right box has 9 letters, 2 being F.
So, the probability of picking Q is:
[tex]P(Q)=\frac{1}{9}[/tex]And the probability of picking F is:
[tex]P(F)=\frac{2}{9}[/tex]The probability of picking Q and F is:
[tex]\begin{gathered} P(Q)\times P(F) \\ \frac{1}{9}\times\frac{2}{9}=\frac{2}{9\times9}=\frac{2}{81} \end{gathered}[/tex]