Respuesta :

PROBLEM:

To find the point-slope form of the equation of the line passing through points (0, 0) and (-4, 7)

METHOD:

The point-slope form of the equation of a line is given to be:

[tex]\begin{gathered} (y-y_0)=m(x-x_0) \\ \text{where} \\ m=\text{ slope} \\ (x_0,y_0)=\text{ Point on the line} \end{gathered}[/tex]

Step 1: Find the slope of the line.

The formula to calculate the slope of a line is given to be:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

We can use the two points provided to find the slope of the line such that:

[tex]\begin{gathered} (x_1,y_1)=(0,0)_{} \\ (x_2,y_2)=(-4,7) \end{gathered}[/tex]

Therefore, the slope is given to be:

[tex]\begin{gathered} m=\frac{7-0}{-4-0} \\ m=-\frac{7}{4} \end{gathered}[/tex]

Step 2: Pick a point on the line to use for the equation.

[tex](x_0,y_0)=(-4,7)[/tex]

Step 3: Use the values gotten from Steps 1 and 2 to write out the equation of the line in the point-slope form:

[tex]\begin{gathered} \Rightarrow y-7=-\frac{7}{4}(x-\lbrack-4\rbrack) \\ \therefore \\ y-7=-\frac{7}{4}(x+4) \end{gathered}[/tex]

ANSWER:

The slope-intercept form of the line is given to be:

[tex]y-7=-\frac{7}{4}(x+4)[/tex]