Given:
The velocity of the electron is
[tex]v=4.3\times10^6\text{ m/s}[/tex]The strength of the uniform magnetic field is B = 3.5 T
The angle between the velocity of the electron and the magnetic field is 55 degrees.
Also, the charge on the electron is
[tex]e\text{ =1.6}\times10^{-19\text{ }}C[/tex]To find the magnetic force on the electron.
Explanation:
The magnetic force can be calculated as
[tex]\begin{gathered} F=\text{Bev sin }\theta \\ =3.5\times1.6\times10^{-19}\times4.3\times10^6sin(55^{\circ}\text{)} \\ =2\times10^{-12}\text{ N} \end{gathered}[/tex]Final Answer: The magnetic force on the electron is 2 x 10^(-12) N
