A ball is dropped from a 70-m building. The height (in meters) after t sec is given by h (t) =-4.9t^2+ 70.(a) Find h(1) and h (1.5).(b) Interpret the meaning of the function values found in part (a).Part: 0 / 4Part 1 of 4) (a) h(1)=0xХ5立

Respuesta :

Given the Quadratic Function:

[tex]h(t)=-4.9t^2+70[/tex]

(a) You need to substitute this value of "t" into the function and evaluate:

[tex]t=1[/tex]

In order to find:

[tex]h(1)[/tex]

Then, you get:

[tex]h(1)=-4.9(1)^2+70[/tex][tex]h(1)=65.1[/tex]

You need to substitute this value of "t" into the function and evaluate:

[tex]t=1.5[/tex]

In order to find:

[tex]h(1.5)[/tex]

Then, you get:

[tex]h(1.5)=-4.9(1.5)^2+70[/tex][tex]h(1.5)=58.975[/tex]

(b) You know that "h" represents the height of the ball after it is dropped (in meters) and "t" represents the time (in seconds) after it is dropped. Therefore:

1. Having this function value:

[tex]h(1)=65.1[/tex]

You can conclude that, after 1 second, the height of the ball is:

[tex]65.1\text{ }meters[/tex]

2. Having this function value:

[tex]h(1.5)=58.975[/tex]

You can conclude that, after 1.5 seconds, the height of the ball is:

[tex]58.975\text{ }meters[/tex]

Hence, the answers are:

(a)

[tex]h(1)=65.1[/tex]

[tex]h(1.5)=58.975[/tex]

(b) - Interpretation for this function value:

[tex]h(1)=65.1[/tex]

After 1 second, the height of the ball is:

[tex]65.1\text{ }meters[/tex]

- Interpretation for this function value:

[tex]h(1.5)=58.975[/tex]

After 1.5 seconds, the height of the ball is:

[tex]58.975\text{ }meters[/tex]