Answer:
The equation of the line is;
[tex]y=-x+3[/tex]Explanation:
We want to find the equation of the line with slope -1 and passes through the point (2,1).
Applying the point slope equation of line;
[tex]y-y_1=m(x-x_1)[/tex]substituting the slope and the point;
[tex]\begin{gathered} y-1=-1(x-2) \\ y-1=-x+2 \\ y=-x+2+1 \\ y=-x+3 \end{gathered}[/tex]Therefore, the equation of the line is;
[tex]y=-x+3[/tex]