Given:
[tex]2,8,10,18,26\ldots[/tex]The above series is an arithemetic series.
The first term of the series is: a=2
The second term of the series is: b=10
The common difference of the series is,
[tex]\begin{gathered} d=b-a \\ =10-2 \\ =8 \end{gathered}[/tex]The expression to calculate the n th term of the series is,
[tex]a_n=a+(n-1)d[/tex]Substitute n=13 in the above expression to calculate the 13 th term.
[tex]\begin{gathered} a_{13}=2+(13-1)\times8 \\ =2+12\times8 \\ =2+96 \\ =98 \end{gathered}[/tex]Thus, the 13th term of the sequence is 98.
