The given system is:
[tex]\begin{gathered} 8x+11y=37 \\ 8x+y=7 \end{gathered}[/tex]
Notice that the coefficients of x in both equations are the same.
Therefore, Subtract the first equation form the second to eliminate the variable x:
[tex]\begin{gathered} 8x-8x+11y-y=37-7 \\ 10y=30 \\ y=\frac{30}{10}=3 \end{gathered}[/tex]
Substitute y = 3 into the second equation:
[tex]\begin{gathered} 8x+3=7 \\ 8x=7-3=4 \\ x=\frac{4}{8}=\frac{1}{2} \end{gathered}[/tex]
Hence, the solution of the system is:
x = 1/2 and y = 3
