This is an instance of conditional probability and the formula to use is;
[tex]P(\text{AIB)}=\frac{P(A\cap B)}{P(B)}[/tex]
Where:
P(A|B) = the probability of event A occurring given that event B occurred
P(A ∩ B) = the probability that both events A and B occur
P(B) = the probability of event B
[tex]\begin{gathered} P(\text{AnB)}=\frac{1}{3} \\ P(B)=\frac{2}{5} \end{gathered}[/tex][tex]P(\text{AIB)}=\frac{\frac{1}{3}}{\frac{2}{5}}=\frac{1}{3}\times\frac{5}{2}=\frac{5}{6}[/tex]
Therefore, the probability that A occurs given that B occurs is 5/6
