ANSWER:
0.011 J
STEP-BY-STEP EXPLANATION:
Given:
q = 150 μC
v = 75 V
r = 0.2
We calculate the work as the product between the charge and the potential difference, just like this:
[tex]\begin{gathered} W=q\cdot v \\ W=150\cdot10^{-6}\cdot75 \\ W=0.01125\text{ J} \\ W\cong0.011\text{ J} \end{gathered}[/tex]The work required is 0.011 J
