ANSWER:
90.9%
STEP-BY-STEP EXPLANATION:
Given:
Input force = 11 N
Distance 1 = 0.4 m
Weight = 40 N
Distance 2 = 0.1 m
We calculate the work in each case to then calculate the efficiency of the machine, just like this:
[tex]\begin{gathered} W_1=11\cdot0.4=4.4\text{ J} \\ W_2=40\cdot0.1=4\text{ J} \\ \text{ Therefore:} \\ e=\frac{W_2}{W_1}\cdot100 \\ e=\frac{4}{4.4}\cdot100 \\ e=90.9\% \end{gathered}[/tex]The efficiency of the machine is 90.9%
