[tex]\begin{gathered} \text{The nth term of the gp is given as} \\ a_n=ar^{n-1} \\ \text{for number 1} \\ a_1=20,\text{ r=}\frac{60}{20}=3,\text{ n =10} \\ a_{10}=20(3)^{10-1} \\ =20(3)^9 \\ =20(19683) \\ =393660 \end{gathered}[/tex]
for number 2
[tex]\begin{gathered} r\text{ = }\frac{2.5}{5}=\frac{1}{2} \\ a_{10}=\text{ 5 x (}\frac{1}{2})9 \\ \\ =5\text{ x }\frac{1}{512} \\ =\frac{5}{512} \\ =0.0097656250 \end{gathered}[/tex]
