We have the segment BC, M is the midpoint
M (4,5)=(xm,ym)
B(0.9) =(x1,y1)
C(x,y)=(x2,y2)
We have the next formula
[tex]xm=\frac{x1+x2}{2}[/tex]
xm=4
x1=0
x2=x
we substitute the values
[tex]4=\frac{0+x}{2}[/tex]
we isolate x
[tex]\begin{gathered} x=4(2) \\ x=8 \end{gathered}[/tex]
the for the coordinate y
[tex]ym=\frac{y1+y2}{2}[/tex]
we have
ym=5
y1=9
y2=y
we substitute the values
[tex]\begin{gathered} 5=\frac{9+y}{2} \\ 10=9+y \end{gathered}[/tex]
then we isolate the y
[tex]\begin{gathered} y=10-9 \\ y=1 \end{gathered}[/tex]
the coordinate of C is (8,1)