SOLUTION:
[tex]f(x)=x^2-4x-14[/tex]The x-intercepts are
[tex]2+3\sqrt{2},\text{ }2-3\sqrt{2}[/tex]The vertex is the point
[tex](2,-18)[/tex]The minimum occurs at x = 2, its value is - 18
The axis of symmetry is the line x = 2
The y-intercept is the point ( 0, -14)
The domain is;
[tex](-\infty,\infty)[/tex]The range is;
[tex](-18,\infty)[/tex]
