If the cooler volume is represented by the cone, we can calculate the volume as:
[tex]V=\frac{1}{3}A_t\cdot h=\frac{1}{3}\pi r^2h[/tex]
where the radius is r = 4 cm and the height is h = 7.46 cm.
We can replace with the values and calculate:
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ V=\frac{1}{3}\pi\cdot4^2\cdot7.46 \\ V=\frac{1}{3}\pi\cdot16\cdot7.46 \\ V\approx125\operatorname{cm}^3 \end{gathered}[/tex]
One cup is equal to 237 cm³, so we can calculate the volume as:
[tex]V=125\operatorname{cm}^3\cdot\frac{1\text{ cup}}{237\operatorname{cm}^3}\approx0.53\text{ cups}[/tex]
Answer: The cone will only fill 0.53 cups of water.
