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The table show the distance traveled over a certain amount of time. What is the value of a that will result in a constant rate of change?Time(hours) Distance(Miles)3 ...2135 ..a8 ........568

Respuesta :

Since it says it increases at a constant rate of change, we can use proportional relationships to solve this problem:

[tex]\begin{gathered} \frac{213}{3}=\frac{a}{5} \\ 213\times5=3a \\ 1065=3a \\ a=\frac{1065}{3}=355 \end{gathered}[/tex]

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