Graph the following function:
[tex]y=x^2+4x-4[/tex]We can give x a set of values and calculate the corresponding values for y.
x = -5
[tex]\begin{gathered} y=(-5)^2+4(-5)-4 \\ \\ y=25-20-4=1 \end{gathered}[/tex]The first point is (-5, 1)
x = -4
[tex]\begin{gathered} y=(-4)^2+4(-4)-4 \\ \\ y=16-16-4=-4 \end{gathered}[/tex]The point is (-4, -4)
x = -3
[tex]\begin{gathered} y=(-3)^2+4(-3)-4 \\ \\ y=9-12-4=-7 \end{gathered}[/tex]Point (-3, -7)
x = -2
[tex]\begin{gathered} y=(-2)^2+4(-2)-4 \\ \\ y=4-8-4=-8 \end{gathered}[/tex]Point (-2, -8)
x = -1
[tex]\begin{gathered} y=(-1)^2+4(-1)-4 \\ \\ y=1-4-4=-7 \end{gathered}[/tex]Point (-1, -7)
x = 0
[tex]\begin{gathered} y=(0)^2+4(0)-4 \\ \\ y=0-0-4=-4 \end{gathered}[/tex]Point (0, -4)
Finaly, use x = 1:
[tex]\begin{gathered} y=(1)^2+4(1)-4 \\ \\ y=1+4-4=1 \end{gathered}[/tex]Point (1, 1)
Plotting the points and drawing the graph:
