Respuesta :

Explanation

The slope-intercept equation of a line has the form

[tex]y=m\cdot x+b,[/tex]

where m is the slope of the line and b is its y-intercept.

Now, there is a very interesting relationship between the slopes (m_1 and m_2) of perpendicular lines:

[tex]m_1=-\frac{1}{m_2}\text{.}[/tex]

Looking at the given equation, we can say that its slope is 1/2. Then,

[tex]m=-\frac{1}{\frac{1}{2}}=-2.[/tex]

Then, our desired equation becomes

[tex]y=-2x+b\text{.}[/tex]

Now, we know that our line passes through (-2,5). This means that

[tex]5=-2\cdot(-2)+b\text{.}[/tex]

Solving this equation for b, we get

[tex]\begin{gathered} 5=4+b, \\ 4+b=5, \\ b=5-4, \\ b=1. \end{gathered}[/tex]

Answer

The desired line has equation

[tex]y=-2x+1.[/tex]