The form of point-slope of the linear equation is
[tex]y-y_1=m(x-x_1)[/tex]Where:
m is the slope of the line
x1 , y1 are the coordinates of a point on the line
Perpendicular lines have additive multiplicative inverse slopes which means the product of their slopes is -1
If the slope of one is m, then the slope of the other is - 1/m
We change its sign and reverse its value
m * -1/m = -1
Since the slope of the line is -3/4
Then the slope of the line perpendicular to it is 4/3
We changed the sign and reciprocal the fraction
Therefor m = 4/3
The line passes through the point (3, 2)
Then x1 = 3 and y1 = 2
Let us substitute m, x1, y1 in the form of the equation above
[tex]y-2=\frac{4}{3}(x-3)[/tex]This is the form of the equation
