[tex]\begin{gathered} We\text{ know that } \\ \angle FAB\cong\angle\text{GED},\text{ and since C is the midpoint of AE:} \\ AC=CE \end{gathered}[/tex][tex]\begin{gathered} \text{ Now, by alternate internal angles, we know that} \\ \angle ACB\cong\angle DCE \\ \text{ And that the supplementary angles of We have two triangles that have two angles congruent, and a common segment of that angles that is congruent. So by Angle Side Angle propierty (ASA), the triangles are congruent
