The area of rectangle B is given as 24.
The length measures 8 units and this means the width would measure
[tex]\begin{gathered} A=l\times w \\ 24=8\times w \\ \frac{24}{8}=w \\ 3=w \\ \text{The width of rectangle B is 3} \end{gathered}[/tex]If the rectangles are similar, then that also means the length of rectangle B and the length of rectangle C are in the same proportion as their width.
The width of rectangle C is derived as shown;
[tex]\begin{gathered} \frac{8}{3}=\frac{2}{w} \\ \text{Cross multiply and you have} \\ w=\frac{2\times3}{8} \\ w=\frac{3}{4} \\ \text{Therefore, the area of rectangle C is derived as;} \\ A=l\times w \\ A=2\times\frac{3}{4} \\ A=1.5 \end{gathered}[/tex]