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You order a glass of lemonade, 150 mL, in a restaurant only to discover that it is warm and too sweet. The sugar concentration of the lemonade is 2.27 M but you would like it to be reduced to a concentration of 1.88 M.How many moles of sugar are in the lemonade solution?

Respuesta :

Answer:

0.3405moles.

Explanations:

In order to get the moles of sugar, we need to get the final volume using the dilution factor as shown below:

[tex]C_1V_1=C_2V_2[/tex]

where:

• C1 and C2 are the, initial and final ,concentration

,

• V1 and V2 are the, initial and final, volume

Given the following parameters:

C1 = 2.27M

V1 = 150mL = 0.15L

C2 = 1.88M

V2 = ?

Substitute the given parameters into the formula:

[tex]\begin{gathered} 2.27\times0.15=1.88\times V_2 \\ 0.3405=1.88V_2 \\ V_2=\frac{0.3405}{1.88} \\ V_2=0.181L \end{gathered}[/tex]

Next is to get the moles of sugar in the lemonade solution using the formula below:

[tex]\begin{gathered} \text{Molarity}=\frac{\text{number of mole}}{volume} \\ n=vM \\ n=0.181L\times1.88\frac{mol}{L} \\ n=0.3405moles \end{gathered}[/tex]

Hence the number of moles of sugar that are in the lemonade solution is 0.3405moles.

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