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29. [-/10 Points]DETAILSSERCPWA11 4.WA.010.An object of mass 0.77 kg is initially at rest. When a force acts on It for 2.9 ms It acquires a speed of 15.5 m/s. Find the magnitude (In N) of the average force acting on the object during the2.9 ms time interval.

Respuesta :

We have:

m = mass = 0.77 kg

t = time = 2.9 ms = 0.0029 s

vf = final speed = 15.5 m/s

vi= initial speed = 0 m/s

Apply:

• F = m (vf-vi) / t

Replacing:

F = 0.77 (15.5 - 0 )/0.0029

F= 4,155.5 N