Respuesta :
Answer:
Explanations:
Given the chemical reaction
[tex]Ag_2SO_4+2KCl\rightarrow2AgCl+K_2SO_4[/tex]Given the following
Mass of Ag2SO4 = 30grams
Mass of KCl = 10grams
Determine the moles of the reactants
[tex]\begin{gathered} mole\text{ of Ag}_2SO_4=\frac{mass}{molar\text{ mass}}molar\text{ mass} \\ mole\text{ of Ag}_2SO_4=\frac{30g}{311.799} \\ mole\text{ of Ag}_2SO_4=0.0962moles \end{gathered}[/tex][tex]\begin{gathered} mole\text{ of KCl}=\frac{10g}{74.5513} \\ moleof\text{ KCl}=0.1341moles \\ 1mole\text{ of KCl}=\frac{0.1341}{2}=0.06707moles \end{gathered}[/tex]B) B) Since the 1 moles of KCl is lower than the moles of Ag2SO4, hence KCl willl be the limiting reactant.
A) A) According to stoichiometry, 2 moles of KCl produces 2 moles of AgCl, the mass of AgCl produced will be given as;
[tex]\begin{gathered} mass=mole\times molar\text{ mass} \\ mass\text{ of AgCl}=0.1341\times143.32 \\ mass\text{ of AgCl}=19.22grams \end{gathered}[/tex]C) According to stoichiometry, 2 moles of KCl produces 1 moles of K2SO4, the mole of K2SO4 produced is;
[tex]\begin{gathered} mole\text{ of }K_2SO_4=\frac{1}{2}\times0.1341 \\ mole\text{ of }K_2SO_4=0.06707moles \end{gathered}[/tex][tex]\begin{gathered} mass\text{ of K}_2SO_4=mole\times molar\text{ mass} \\ mass\text{ of K}_2SO_4=0.06707\times174.259 \\ mass\text{ of K}_2SO_4=11.69grams \end{gathered}[/tex]