Answer
The volume will be 0.61 L or 610 mL
Explanation
Given:
Initial volume, Vā = 500.0 mL = 0.5 L
Initial temperature, Tā = 27 Ā°C = (27 + 273.15) = 300.15 K
Initial pressure, Pā = 755 mmHg = 0.993 atm
Final temperature, Tā = -33 Ā°C = 240.13 K
Final pressure, Pā = 0.65 atm
What to find:
The final volume,, V.
Solution:
The combined gas law equation is given by:
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} \\ \\ \end{gathered}[/tex]Put the values of the parameters into the combined law equation:
[tex]\begin{gathered} \frac{0.993atm\times0.5L}{300.15K}=\frac{0.65atm\times V_2}{240.15\text{ }K} \\ \\ \frac{0.4965\text{ }atm.L}{300.15\text{ }K}=\frac{0.65atm\times V_2}{240.15\text{K}} \\ \\ Cross\text{ }multiply \\ \\ V_2\times0.65atm\times300.15\text{ }K=240.15K\times0.4965\text{ }atm.L \\ \\ V_2=\frac{240.15K\times0.4965\text{ }atm.L}{0.65atm\times300.15K} \\ \\ V_2=0.611\text{ }L \end{gathered}[/tex]The volume will be 0.61 L or 610 mL
