First, if we sketch the situation, we have the following:
We'll use the energy approach to solve the problem. We need to find out the displacement in the y axis. This can be achieved by finding the opposing catete, which is
[tex]y=2.2*sin(18°)=0.68m[/tex]This is how much it has traveled in the y axis. Its initial energy (gravitational potential) can be written as:
[tex]E=mgh=5.25*9.8*0.68=34.986J[/tex]By the end, this same energy will have been turned into kinetic energy, thus:
[tex]34.986=\frac{mv^2}{2}=\frac{5.25*v^2}{2}[/tex]So we know that
[tex]v^2=\frac{2*34.986}{5.25}[/tex]And finally
[tex]v=\sqrt[\placeholder{⬚}]{\frac{2*34.986}{5.25}}=3.65\frac{m}{s}[/tex]Then, our final answer is 3.65m/s
