The given sequence is 2,6,10,16,...
To obtain an expression for the general expression for the nth term, we will use the formula:
[tex]\begin{gathered} T_n=a+(n-1)d \\ WhereT_{n=}the\text{ nth term, a = the first term, n = the nth position in the series, d = the common difference,} \\ a=2,\text{ d = 6-2 =4 } \\ T_n=2+(n-1)4 \\ T_n=2+4n-4 \\ T_n=4n-2 \end{gathered}[/tex]Thus, the nth term is Tn= 4n - 2.
