For the given rectangle:
The area for a rectangle is given by:
[tex]a_r=Length\cdot Width[/tex]
Replacing the values:
[tex]a_r=33\cdot30[/tex]
Then:
[tex]a_t=990[/tex]
Now, the perimeter is given by:
[tex]P=2Length+2Width[/tex]
Replacing:
[tex]P=2(33)+2(30)[/tex][tex]P=126[/tex]
For dilated triangle:
The big triangle is dilated by a scale of 1/3.
Therefore, each side is dilated by this factor:
For 33 = 33(1/3) = 11
For 30 = 30(1/3) = 10
Now, to find the perimeter:
[tex]P=2Length+2Width[/tex][tex]P=2(11)+2(10)[/tex][tex]P=42[/tex]
To find the area:
[tex]a_r=Length\cdot Width[/tex][tex]a_t=11\cdot10[/tex]
Then
[tex]a_t=110[/tex]
