(b) If m∠DBC is three times that of m∠ABE, find m∠DBC.

Angle DBC=3*Angle ABE
Angle DBC+Angle ABE+Angle EBD=180
Angle EBD=90
[tex]\begin{gathered} \measuredangle DBC+\measuredangle ABE+90=180 \\ 3\cdot\measuredangle ABE+\measuredangle ABE+90=180 \\ 4\cdot\measuredangle ABE+90=180 \\ 4\cdot\measuredangle ABE=180-90 \\ 4\cdot\measuredangle ABE=90 \\ \measuredangle ABE=\frac{90}{4}=22.5 \end{gathered}[/tex]Angle DBC will be
[tex]\begin{gathered} \measuredangle DBC=3\cdot\measuredangle ABE \\ \measuredangle DBC=3\cdot(22.5) \\ \measuredangle DBC=67.5 \end{gathered}[/tex]