Given:
The mass of the block, m=54.3 kg
The angle of inclination, θ=42.4°
To find:
The accleration of the block.
Explanation:
The free-body diagram:
Referring to the diagram, N is the normal force, g is the acceleration due to gravity.
The only force acting on the block in the horizontal direction is the horizontal component of gravity.
Thus the net force on the block is given by,
[tex]\begin{gathered} ma=mgsin\theta \\ \Rightarrow a=gsin\theta \end{gathered}[/tex]
Where a is the acceleration of the block.
On substituting the known values,
[tex]\begin{gathered} a=9.8\times sin42.4\degree \\ =6.61\text{ m/s}^2 \end{gathered}[/tex]
Final answer:
The acceleration of the block is 6.61 m/s²
