We want to solve
[tex]\frac{1}{3}x+\frac{4}{9}=\frac{7}{9}[/tex]We can subtract 4/9 on both sides.
[tex]\begin{gathered} \frac{1}{3}x+\frac{4}{9}-\frac{4}{9}=\frac{7}{9}-\frac{4}{9} \\ \\ \frac{1}{3}x=\frac{7}{9}-\frac{4}{9} \\ \\ \frac{1}{3}x=\frac{7-4}{9} \\ \\ \frac{1}{3}x=\frac{3}{9} \end{gathered}[/tex]Now we have 3/9 on the right side, but we can simplify that fraction to 1/3
[tex]\begin{gathered} \frac{1}{3}x=\frac{3}{9} \\ \\ \frac{1}{3}x=\frac{1}{3} \end{gathered}[/tex]And now we have the result!
[tex]x=1[/tex]Therefore the final result is x = 1
