Since we are rolling a die twice
The possible out come of rolling a die is
[tex]\mleft\lbrace1,2,3,4,5,6\mright\rbrace[/tex]
Therefore, the probability of getting a 4 on every roll is
[tex]P(\text{getting a 4 on every roll) }=P(1st\text{ 4) and P(2nd 4)}[/tex]
From the sample outcome above
P(of 4) = 1/6
Therefore
[tex]\begin{gathered} P(\text{getting a 4 on every roll)}=\frac{1}{6}\times\frac{1}{6} \\ P(\text{getting a 4 on every roll)}=\frac{1}{36} \\ P(\text{getting a 4 on every roll)}=0.0278 \end{gathered}[/tex]
Therefore, thr porbability is 0.0278
