giving the vector
V=-10i + 16j
then
the magnitude of the vector is giving by the hypotenuse
then
[tex]Mag=\sqrt{16^2+10^2}[/tex][tex]Mag=2\sqrt{89}=18.867[/tex]
the direction angle is giving by
[tex]tan(\theta)=\frac{Opp}{Adj}[/tex][tex]tan(\theta)=\frac{16}{10}[/tex][tex]\theta=arctan(1.6)[/tex][tex]\theta=arctan(1.6)=57.99\degree[/tex]
rounded to one decimal place
then the direction is 58.0
