MoncerratY553512 MoncerratY553512

26-10-2022
Mathematics

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Given parallelogram PQRS below, RT = 88. If TP = x+6, solve for x.

Given parallelogram PQRS below RT 88 If TP x6 solve for x class=

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PadraigE599070 PadraigE599070

26-10-2022

The diagonals of a parallelogram bisect each other. Therefore:

[tex]\begin{gathered} RT=TP \\ so\colon \\ 88=x+6 \\ x=88-6 \\ x=82 \end{gathered}[/tex]

Answer:

x = 82

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