Determine the cost of a taxi trip of 9 2/3 miles if the fare is $1.10for the first 1/6 mile and $.20 for each additional 1/6 mile(or fraction).a. $11.90b. $11.20c. $12.50d. $12.80

Respuesta :

[tex]c)$\$12.50$[/tex]

1) Let's begin with converting that Mixed Number to an Improper fraction:

[tex]9\frac{2}{3}=\frac{3\times9+2}{3}=\frac{29}{3}[/tex]

2) Since the fare is given in terms of each 1/6 of a mile we can write that dividing that length of the trip by 1/6:

[tex]\frac{29}{3}\div\frac{1}{6}=\frac{29}{3}\times6=\frac{174}{3}=58[/tex]

So this division tells us that there are 58 segments of 1/6 of a mile. Therefore we can write out:

[tex]\begin{gathered} 1(1.10)+57(0.20) \\ 1.10+11.4 \\ 12.50 \end{gathered}[/tex]

the first 1/6 mile times 1.10 plus 57 other 1/6 of mile times 0.20

Hence, the answer is "c"