We find the directed line segment AB, as follows:
We subtract the x and y component of the first coordinate from the second one, that is:
[tex]AB=(6-(-3),1-(-2))\Rightarrow AB=(9,3)[/tex]Now, we proceed as follows:
We will use the ratio 2:1 to solve in the following expression to find the x and y coordinates for the point P:
[tex](x_1+\frac{a}{a+b}(x_2-x_1),y_1+\frac{a}{a+b}(y_2-y_1))[/tex]This expression is for a rate of the form a:b.
That is:
[tex](-3+\frac{2}{2+1}(6-(-3)),-2+\frac{2}{2+1}(1-(-2)))=(3,0)[/tex]From this, we have that the point p is (3, 0).
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You can only find the coordinates of the P point by using the formula
